Question

5x-3y=0, x+4y=20 solve this​

Answer 1

Answer:

5x_3y=0 _____(i)

x+4y=20______(ii)

multiplying eq i by 4

4(5x_3y)=4(0)

20x_12y=0 ____iii

multiplying the ep ii by 3

3(x+4y)=3(20)

3x+12y=60 _____iv

subtracting eq iii from eq iv

20x_12y=0

+3x+12y=+60

__________

23x =60

23x=60

x=60/23 ans

putting value of x = 60/23 in eq i

5x-3y=0

5(60/23)_3y=0

300/23 _3y=0

_3y = 0-300/23

-3y = _300/23

y = 300/23of3

y = 100/23 answer