Question

5x+3y+1=0,4x+3y-1=0

by substitution​

Answer 1

Answer:

5x+3y+1=0

and, 4x+3y-1=0

now, 5x+3y+1-4x-3y+1=0

= 2x= 2

x= 1

now, 5×1+3y+1=0

=5+1+3y=0

= 6+3y=0

. = 3y= -6

y= -2

ans= x=1,y=-2