5x+3y+11=0 and 2x+4y= -10
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Given:
We have two equations 5x+3y+11=0 and 2x+4y= -10.
To Find:
We have to solve these equations?
Step-by-step explanation:
- We have two equations 5x+3y+11=0 and 2x+4y= -10. we will solve them by substitution method.
[tex] 5x+3y+11=0\\ and\\ 2x+4y= -10\\\\ x=\frac{-11-3y}{5}\\ \textrm{Put the value of x in other equation}\\\\ 2(\frac{-11-3y}{5} )+4y=-10\\ -22-6y+20y=-50\\ 14y=-50+22\\ 14y=-28\\ y=-2\\ \textrm{Put the value of y }\\ x=\frac{-11+6}{5} =-1[/tex]
Thus, value of x=-1 , y=-2.
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