Question

5x-3y=11 ; -10x+6y=-22​

Answer 1

Answer:

Given,

$5x - 3y = 11 \\ = > 5x = 11 + 3y \\ = > x = \frac{11 + 3y}{5} \: \: \: \: ...equation \: 1$

Now, putting the value of x from equation 1.

$= > 10 \times \frac{11 + 3y}{6y} = 22 \\ 2(11 + 3y) + 6y = 22 \\ = > 22 + 6y + 6y = 22 \\ = > 12y = 22 - 22 \\ = > y = \frac{22 - 22}{12} = 0 \\ = > y = 0$

Now value of x

$= \frac{11 + 3y}{5} = \frac{11 + 3}{0} = \frac{11 + 0}{5} = \frac{11}{5} = \frac{11}{5}$

Therefore, x = 11/5 and y = 0