Question

5x+3y=-11 ,2x+4y=-10 solve by crammers method​

Answer 1

Answer:

this is the answer of this crammers method

Answer 2

Step-by-step explanation:

Given: We have 2 equations  $5x+3y=-11$ and $2x+4y=-10$

To find: Value of (x,y)

For calculation of the above equation,

By using the Crammers Method,

i. Calculating D.

⇒ $D=\left[\begin{array}{ccc}5&3\\2&4\end{array}\right]$

⇒ $(5x4) - (2x3)$

⇒ $20-6=14$

ii. Calculating $D_{x}$

⇒ $D\left[\begin{array}{ccc}-11&3\\-10&4\end{array}\right]$

⇒ $(-11) x 4 - (-10) x 3$

⇒ $-44 - (-30)$

⇒ $-44 +30 = -14$

iii. Calculating $D_{y}$

⇒ $D=\left[\begin{array}{ccc}5&-11\\2&-10\end{array}\right]$

⇒ $5 x (-10) -2 x (-11)$

⇒ $-50 - (-22)$

⇒ $-50 + 22 = -28$

For calculation of x,

⇒ $x= \frac{D_{x}}{D}$

⇒ $\frac{-14}{14} = -1$

For calculation of y,

⇒ $y=\frac{D_{y}}{D}$

⇒ $\frac{-28}{14} = -2$

The answer is $(x,y) = (-1,-2)$.