5x-3y=140
2x-2y=60
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5x-3y=140 ---(1)
2x-2y=60 ----(2)
Multiplying the cofficients
2(5x-3y)=2×140
5(2x-2y)=5×60
So, the equations become
10x-6y=280 (elimination method)
10x-10y=300
- + -
____________
4y = -20
____________
y=-20/4
y=-5
2x-2y=60
2x -2×(-5)=60
2x+10=60
2x=60-10
2x=50
x=50/2
x=25
So, x=25 and y =-5
2x-2y=60 ----(2)
Multiplying the cofficients
2(5x-3y)=2×140
5(2x-2y)=5×60
So, the equations become
10x-6y=280 (elimination method)
10x-10y=300
- + -
____________
4y = -20
____________
y=-20/4
y=-5
2x-2y=60
2x -2×(-5)=60
2x+10=60
2x=60-10
2x=50
x=50/2
x=25
So, x=25 and y =-5
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