Question

5x-3y=140
2x-2y=60
xतथाyका मान निकाले

Answer 1

5x-3y=140 ---(1)

2x-2y=60 ----(2)

Multiplying the cofficients

2(5x-3y)=2×140

5(2x-2y)=5×60

So, the equations become

10x-6y=280 (elimination method)
10x-10y=300
- + -
____________
4y = -20
____________


y=-20/4

y=-5

2x-2y=60

2x -2×(-5)=60

2x+10=60

2x=60-10

2x=50

x=50/2

x=25


So, x=25 and y =-5