5x +3y=35 and 2x+4y=28 by algebraic
method
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multiply first equation by 2 and second equation by 5
10x+6y=70
10x+20y=140
subtract the 2 equations. Gives 14y=70. y=5
substitute for y in first equation. 5x+15=35
5x=20
x=4
therefore x=4 and y=5
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