Question

5x + 3y = 53
x = 6y+4??????


please help me by substituting

Answer 1

Equation (1),

$5x + 3y = 53$

Equation (2),

$x = 6y + 4$

Equating the value of "x" in equation in Equation (1), we get:

$5(6y + 4) + 3y = 53$

$30y + 20 + 3y = 53$

$33y + 20 = 53$

$33y = 53 - 20$

$33y = 33$

$y = \frac{33}{33} = 1$

$x = 6y + 4$

$x = 6(1) + 4$

$x = 6 + 4 = 20$

Hope you understand the question.

If you really like the answer, mark this answer as Brainliest Answer.

ThankYou..