Question

-5x+3y=-6 9x-4y=1 elimination method

Answer 1

Given Equation

-5x + 3y = -6 (i)

9x - 4y = 1 (ii)

To Find

Value of x and y by using elimination methods

Now take

-5x + 3y = -6 (i)

9x - 4y = 1 (ii)

Now I want eliminate y so multiple by -4 in (i)eq and 3 in (ii)eq

-5x + 3y = -6 (i) × -4

9x - 4y = 1 (ii) × 3

We get

20x - 12y = 24 (i)

27x - 12y = 3 (ii)

Now Subtracte (ii) from (i)

20x - 12y -(27x - 12y ) = 24 - 3

20x - 12y - 27x + 12y = 21

20x - 27x = 21

-7x = 21

x = -21/7

x = -3

Now put the value of x = -3 on (i)eq

-5x + 3y = -6 (i)

-5(-3) + 3y = -6

15 + 3y = -6

3y = -6 - 15

3y = - 21

y = -21/3

y = -7

Answer

x = -3 and y = -7

Answer 2

Given Equation

-5x + 3y = -6 (i)

9x - 4y = 1 (ii)

To Find

Value of x and y by using elimination methods

Now take

-5x + 3y = -6 (i)

9x - 4y = 1 (ii)

Now I want eliminate y so multiple by -4 in (i)eq and 3 in (ii)eq

-5x + 3y = -6 (i) × -4

9x - 4y = 1 (ii) × 3

We get

20x - 12y = 24 (i)

27x - 12y = 3 (ii)

Now Subtracte (ii) from (i)

20x - 12y -(27x - 12y ) = 24 - 3

20x - 12y - 27x + 12y = 21

20x - 27x = 21

-7x = 21

x = -21/7

x = -3

Now put the value of x = -3 on (i)eq

-5x + 3y = -6 (i)

-5(-3) + 3y = -6

15 + 3y = -6

3y = -6 - 15

3y = - 21

y = -21/3

y = -7

Answer

x = -3 and y = -7