Question

5x+3y_9=0; 2x_3 y =12​

Answer 1

5x+3y=9------(1)

2x-3y=12 ---(2)(adding by Elimination method )

--------------

7x=21

x= 3

put x=3 in equ-----(1)

we get,

$\implies$ 5×3+3y = 9

$\implies$ 15+3y = 9

$\implies$ 3y = 9-15

$\implies$ y= $\frac{-6}{3}$

$\implies$ y = -2

Therefore, $\fbox{x = 3}$ , $\fbox{y = -2}$

Answer 2

Step-by-step explanation:

5x+3y-9=0; 2x-3y =12

5x+3y=9 ; 2x-3y=12

5x+3y =9. ........................................(1)

2x-3y =12. .........................................(2)

adding (1) and (2), we get

5x+3y+2x-3y = 9+12

5x+2x=21 ==> 7x = 21 ==> x=21/7

x = 3. .....................................................(3)

we substitute (3) in (1) we get

5(3)+3y =9. ==> 15+3y =9. ==> 3y =9-15

3y = -6. ==> y = -6/3. ==> y = -2

hence the value of x and y are 3 and -2