5x+3y=9;2x+3y=12 (simultaneous equestion)
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Let 5x+3y=9be first equation
And 2x+3y=12be second equation
Now subtract 2 equation from 1 equation
So by subtraction, we get
3x=-3
So x=-1
Putting value of x in second equation, we get
-2+3y=12
So 3y=14
And y=14/3
Hope you get the answer buddy and please mark brainliest
And 2x+3y=12be second equation
Now subtract 2 equation from 1 equation
So by subtraction, we get
3x=-3
So x=-1
Putting value of x in second equation, we get
-2+3y=12
So 3y=14
And y=14/3
Hope you get the answer buddy and please mark brainliest
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