5x + 3y = 9 -----(I)
2x + 3y = 12 ----- (II)
Let’s add eqations (I) and (II).
Solution is (x, y) = ( ☐ , ☐)
Answers
Answered by
13
Hi ,
5x + 3y = 9 ---( I )
2x + 3y = 12 ---( II )
are two given equations.
subtract equation ( II ) from ( I ) ,we get
3x = - 3
x = -3/3
x = -1 ,
put x = -1 in equation ( I ) , we get
5( -1 ) + 3y = 9
-5 + 3y = 9
3y = 14
y = 14/3
Therefore ,
x = -1 , y = 14/3
I hope this helps you.
: )
5x + 3y = 9 ---( I )
2x + 3y = 12 ---( II )
are two given equations.
subtract equation ( II ) from ( I ) ,we get
3x = - 3
x = -3/3
x = -1 ,
put x = -1 in equation ( I ) , we get
5( -1 ) + 3y = 9
-5 + 3y = 9
3y = 14
y = 14/3
Therefore ,
x = -1 , y = 14/3
I hope this helps you.
: )
Answered by
8
Heya !!
5X + 3Y = 9 ------(1)
And,
2X + 3Y = 12 ------(2)
Subtracting equation (1) and equation (2)
5X + 3Y = 9
2X + 3Y = 12
--------------------
3X = -3
X = -3/3 = -1
Putting the value of X in equation (1)
5X + 3Y = 9
5× -1 + 3Y = 9
-5 + 3Y = 9
3Y = 9+5
Y = 14/3
Hence,
X = -1 and Y= 14/3.
5X + 3Y = 9 ------(1)
And,
2X + 3Y = 12 ------(2)
Subtracting equation (1) and equation (2)
5X + 3Y = 9
2X + 3Y = 12
--------------------
3X = -3
X = -3/3 = -1
Putting the value of X in equation (1)
5X + 3Y = 9
5× -1 + 3Y = 9
-5 + 3Y = 9
3Y = 9+5
Y = 14/3
Hence,
X = -1 and Y= 14/3.
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