5x+4/y=7 And 4x-3/y=5 (solve using cross multiplication method) ICSE
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4x+3y=29 ----- (1)
6x+3y=39 ----- (2)
First use formula for cross multiplication method:
b1c2−b2c1x=c1a2−a1c2y=a2b2−a2b1−1
So, from equation (1) and (2) we can write the value of a, b and c.
3×39−3×29x=29×6−4×39y=4×3−6×3−1
117−87x=174−156y=12−18−1
30x=18y=−6−1
30x=−6−1
x=−6−30=5
18y=−6−1
y=−6−18=3
The solution is (5, 3)
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