Question

(5x-4y+1)^2+(5x+4y)^2​

Answer 1

Answer:

For the given pair of equations 5x+4y=20 and 10x+8y=16;

a

2

a

1

=

10

5

=

2

1

c

2

b

1

=

8

4

=

2

1

c

2

c

1

=

−16

−20

=

4

5

As the given pair of linear equation satisfies -

a

2

a

1

=

b

2

b

1



=

c

2

c

1

The graph will be a pair of parallel lines and so the pair of equations will have no solution.