Question

5x+4y=1, 3x-6y=2
Solve by substitution method

Answer 1

Solve equation [2] for the variable x

[2] 3x = 6y + 2

[2] x = 2y + 2/3

// Plug this in for variable x in equation [1]

[1] 5•(2y+2/3) + 4y = 1

[1] 14y = -7/3

[1] 42y = -7

// Solve equation [1] for the variable y

[1] 42y = - 7

[1] y = - 1/6

// By now we know this much :

x = 2y+2/3

y = -1/6

// Use the y value to solve for x

x = 2(-1/6)+2/3 = 1/3

Solution :

{x,y} = {1/3,-1/6}