5x+4y=1, 3x-6y=2
Solve by substitution method
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Solve equation [2] for the variable x
[2] 3x = 6y + 2
[2] x = 2y + 2/3
// Plug this in for variable x in equation [1]
[1] 5•(2y+2/3) + 4y = 1
[1] 14y = -7/3
[1] 42y = -7
// Solve equation [1] for the variable y
[1] 42y = - 7
[1] y = - 1/6
// By now we know this much :
x = 2y+2/3
y = -1/6
// Use the y value to solve for x
x = 2(-1/6)+2/3 = 1/3
Solution :
{x,y} = {1/3,-1/6}
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