5x-4y+2=0, 2x+3y=13
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1
Answer:
Given equations:-
x
2
+
y
3
=13and
x
5
−
y
4
=−2
Let
x
1
=pand
y
1
=q
Thus, we have,
2p+3q=13=>2p+3q−13=0
5p−4q=−2=>5p−4q+2=0
Using cross-multiplication method to solve the equations we have,
(3)(2)−(−4)(−13)
p
=
(−13)(5)−(2)(2)
q
=
(2)(−4)−(5)(3)
1
6−52
p
=
−65−4
q
=
−8−15
1
−46
p
=
−69
q
=
−23
1
=>
−46
p
=
−23
1
or,p=2
=>
−69
q
=
−23
1
or,q=3
Now,p=
x
1
=2=>x=
2
1
andq=
y
1
=3=>y=
3
1
∴x=
2
1
andy=
3
1
Step-by-step explanation:
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