Question

5x+4y-4=0 x-12y-20=0 in substitution method ​

Answer 1

Step-by-step explanation:

$5x + 4y - 4 = 0 \\ 5x + 4y = 4 \\ 5x = 4 - 4y \\ x = \frac{4 - 4y}{5} \\ put \: the \: value \: of \: x \: in \: equation \: 2 \\ x - 12y - 20 = 0 \\ \frac{4 - 4y}{5} - 12y = 20 \\ \frac{4 - 4y - 60y}{5} = 20 \\ 4 - 4y - 60y = 20 \times 5 \\ - 64y = 100 - 4 \\ y = \frac{96}{64} \\ y = 1.5 \\ now \: \: put \: the \: value \: of \: y = 1.5 \: in \: eqation \: 1 \\ 5x + 4y - 4 = 0 \\ 5x + 4 \times 1.5 = 4 \\ 5x = 4 - 6 \\ x = \frac{ - 2}{5} \\ x = - 0.4$