Question

5x + 4y - 4= 0
x - 12y – 20 = 0 solve it by elimination method



please answer this fast​

Answer 1

Answer:

Answer is explained in the figure below.

Hope this helps u!!!

Answer 2

The correct answer is "x = 2" and "y = $\frac{-3}{2}$". Further explanation is given below.

Step-by-step explanation:

Given :

5x+4y-4 = 0...(equation 1)

x-12y–20 = 0...(equation 2)

On multiplying equation "2" from "5", we get

5(x-12y–20) = 0

5x-60y-100 = 0...(equation 3)

On subtracting equation "1" from equation "3", we get

⇒  5x+4y-4-(5x-60y-100) = 0

⇒  5x+4y-4-5x+60y+100 = 0

⇒  4y+60y-4+100 = 0

⇒  64y+96 = 0

⇒  64y = -96

⇒  y = $\frac{-96}{64}$

⇒  y = $\frac{-3}{2}$

On putting the value of "y" in equation "1", we get

⇒  5x+4( $\frac{-3}{2}$) = 4

⇒  5x-6 = 4

⇒  5x = 4+6

⇒  5x = 10

⇒  x = $\frac{10}{5}$

⇒  x = 2

Learn more:

Find...

https://brainly.in/question/15247500