Math, asked by naveedsoha20, 5 days ago

5x+4y=4
x-20=12y
please help me solve this

Answers

Answered by somrajchanak
1

Answer:

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Class 12

>>Applied Mathematics

>>Linear Equations

>>Solving a Pair of Linear Equations - Substitution Method

>>Solve the following system of equations

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Solve the following system of equations by the method of substitution:

5x+4y−4=0, x−20=12y

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Solution

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Given equations are

5x+4y=4 ....(1)

and x−20=12y ....(2)

Therefore, x=12y+20 ....(3)

Substitute this value of x in equation (1), we get

5(12y+20)+4y=4

⇒60y+100+4y=4

⇒64y=−96

⇒y=−

64

96

⇒y=−

2

3

Put this value in equation (3),

x=12(−

2

3

)+20

⇒x=−18+20=2

Therefore, the solution is x=2,y=−

2

3

.

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