5x+4y=4
x-20=12y
please help me solve this
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Class 12
>>Applied Mathematics
>>Linear Equations
>>Solving a Pair of Linear Equations - Substitution Method
>>Solve the following system of equations
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Solve the following system of equations by the method of substitution:
5x+4y−4=0, x−20=12y
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Given equations are
5x+4y=4 ....(1)
and x−20=12y ....(2)
Therefore, x=12y+20 ....(3)
Substitute this value of x in equation (1), we get
5(12y+20)+4y=4
⇒60y+100+4y=4
⇒64y=−96
⇒y=−
64
96
⇒y=−
2
3
Put this value in equation (3),
x=12(−
2
3
)+20
⇒x=−18+20=2
Therefore, the solution is x=2,y=−
2
3
.
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