5x-[4y-{7x-(3z-2y)+4z-3(x+3y-2z)}]
Answers
Answered by
7
5x-(4y-(7x-(3z-2y)+4z-3kx+3y-2z
= 5x-4y-7x-3z+2y+4z-3x-9y+6z
= 5x-7x - 3x-4y+2y-9y-3z+4z+6z
= - 2x-3x-2y-9y-3z+10z
= - 5x-11y+7z
So the answer is - 5x-11y+7z
= 5x-4y-7x-3z+2y+4z-3x-9y+6z
= 5x-7x - 3x-4y+2y-9y-3z+4z+6z
= - 2x-3x-2y-9y-3z+10z
= - 5x-11y+7z
So the answer is - 5x-11y+7z
PayalAhamad:
1222222
Similar questions