Math, asked by vaishnavlagad, 9 months ago

5x-4y+8=0,7x+6y-9=0​

Answers

Answered by llAloneSameerll
29

{ \sf{ \large{ the \: given \: equations \: are \longrightarrow}}}

 { \rm{5x - 4y + 8 = 0 \longrightarrow(i)}}

 { \rm{7x - 6y  - 9 = 0 \longrightarrow(ii)}}

{ \sf{ \large{ taking \: eq.(i) \longrightarrow}}}

 { \rm{5x - 4y + 8 = 0 }}

 { \rm{ \implies5x  =  4y - 8 }}

 { \rm{ \implies \: x  =   \dfrac{4y - 8}{5}  }}

{ \sf{ \large{ taking \: eq.(ii) \longrightarrow}}}

 { \rm{7x - 6y  - 9 = 0}}

 { \rm{ \implies7( \dfrac{4y - 8}{5})  - 6y  - 9 = 0}}

 { \rm{ \implies\dfrac{28y - 56}{5}  - 6y  - 9 = 0}}

 { \rm{ \implies{28y - 56} - 6y  =9 \times 5}}

 { \rm{ \implies22y =45 + 56}}

 { \rm{ \implies22y =101}}

 { \rm{ \implies y =  \dfrac{101}{22}}}

 { \rm{ \implies y =  4.5}}

{ \sf{ \large{ taking \: eq.(i) \longrightarrow}}}

 { \rm{5x - 4y + 8 = 0 }}

 { \rm{ \implies5x - 4(4.5)+ 8 = 0 }}

 { \rm{ \implies5x - 18+ 8 = 0 }}

 { \rm{ \implies5x  = 18 - 8 }}

 { \rm{ \implies \: x  =  \dfrac{10}{5}  }}

 { \rm{ \implies \: x  =  \dfrac{ { \not10}^{2} }{ \not5}  }}

{  \rm{x = 5}}

{ \tt{ \large{ the \: value \: of \colon}}}

{ \tt{ \large{x = 4.5}}}

{ \tt{ \large{y = 2}}}

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