Question

5x-4y+8=0 7x+6y-9=0

Answer 1

hey friend
$7(5x - 4y + 8 = 0) \\ \\ 5(7x + 6y - 9 = 0) \\ \\ 35x - 28y + 56 = 0 ..........eqn1\\ \\ 35x + 30y - 45 = 0.........eqn2 \\ subtracting \: one \: from \: two \\ \\ we \: get \\ - 58y = - 101 \\ y = 101/58 \\ x = 30/29$

Answer 2

Answer:

$\huge{\pink{\boxed{\green{\sf{\therefore x=\frac{-150}{119}}}}}}$

$\huge{\pink{\boxed{\green{\sf{\therefore y=\frac{101}{238}}}}}}$

Step-by-step explanation:

$\huge{\pink{\boxed{\green{\underline{\red{\sf{SOLUTION-}}}}}}}$

$\: \: \: \: \: \: \: \: \: { \orange{given}} \\{ \pink{ \boxed{ \green {5x - 4y + 8= 0}}}} \\{ \pink{ \boxed{ \green {7x + 6y - 9= 0}}}} \\ \\ { \blue{to \: find}} \\ {\purple{ \boxed{ \red {x = ?}}}} \\ {\purple{ \boxed{ \red {y =?}}}}$

☆ According to given question:

☆ Using Substitution method:

$\to 5x - 4y + 8 = 0 \\ \to 5x = - 8 + 4y \\ \to x = \frac{ - 8 + 4y}{5} - - - - - (1)\\ \\ \to 7x + 6y - 9 = 0 - - - - - (2)\\ substituting \: value \: of \: x \: in \:(2) \\ \to 7 \times ( \frac{ - 8 + 4y}{5} ) + 6y =9 \\ \to \frac{ - 8 + 4y + 30y}{5} = \frac{9}{7} \\ \to - 56 +238y = 45 \\ \to 238y = 45 + 56 \\ { \pink{ \boxed{ \green{\therefore y = \frac{101}{238}}}}} \\ \\ putting \: value \: of \: y \: in \: (1) \\ \to x = \frac{ - 8 + 4 \times ( \frac{101}{238}) }{5} \\ \to x = \frac{ - 8 + \frac{202}{119} }{5} \\ \to x = \frac{ \frac{ - 952 + 202}{119} }{5} \\ \to x = \frac{ \frac{ - 750}{119} }{5} \\ \to x = \frac{ - 750}{119 \times 5} \\ { \pink{ \boxed{ \green{\therefore x = \frac{ - 150}{119} }}}}$

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