Math, asked by akhil147, 1 year ago

5x-4y+8=0 and 7x+6y-7=0
5x - 4y + 8 = 0  and 7x + 6y - 7 = 0

Answers

Answered by sushant2505
5
Hi...☺

Here is your answer...✌
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5x - 4y + 8 = 0 \: \: \: \: ....(1)\\ 7x + 6y - 7 = 0 \: \: \: \: ....(2) \\ \\ from \: eq \: (1) \times 7 \:a nd \: eq(2) \times 5 \\ \\ \: \: 35x - 28y + 56 = 0 \\ \: \: 35x + 30y - 35 = 0 \\ - \: \: \: \: \: \: - \: \: \: \: \: \: \: +\: \: \: \:\: \: \:\:\:\:\:\: \: \:\: \: \: (By\: Subtracting) \\ - - - - - - - - - - - \\ \: \: \: \: \: \: \: \: \: \: \: - 58y + 91 = 0 \\ = > \: \: \: \: \: \: \: \: y = \frac{91}{58} \\ \\ Putting \: value \: of \: y \: in \: eq(1) \\ \\ 5x - 4( \frac{91}{58} ) + 8 = 0 \\ \\ 5x - \frac{182}{29} + 8 = 0 \\ \\ 5x + 8- \frac{182}{29} = 0 \\ \\ 5x + \frac{232 -182}{29} = 0 \\ \\ 5x + \frac{50}{29} = 0 \\ \\ 5x = - \frac{50}{29} \\ \\ x = - \frac{10}{29} \\\\ y = \frac{91}{58}

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Answered by Akash1000
0
x = -10/29 and y = 98/58
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