Question

5x-4y+8=0 and 7x+6y-9=0 find x,y with the help of substitution method.
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Answer 1

Answer:

$solution \: = the \: given \: system \: of \: equation \: is \: \\5x - 4y = - 8 \\ 7x + 6y = 9 \\ \\ from(1) \: we \: get \\ \\ 5x = - 8 + 4y \\ \\ x = \frac{ - 8 + 4y}{5} \\ \\ \: substitution \: \:x = \frac{ - 8 + 4y}{5} \: \: in \: (2)\\ \\ 7x + 6y = 9 \\ 7( \frac{ - 8 + 4y}{5} ) + 6y = 9 \\ \\ - 56 + 28y + 6y = 45 \\ \\ 34y = 100$