Question

5x-4y+8=0 and 7x+6y-9=0 graphical method​

Answer 1

Answer:

Answer is in the attachment

Answer 2

5x-4y+8=0 be equation 1st

7x+6y-9-0 be equation 2nd

solve these two equations to find the

intersection point of these two equation 5x-4y=-8 be equation 1st

7x+6y=9 be equation 2nd

multiply 1st equation by 3 and multilply

2nd

equation by 2 to gey the coefficient

of y equal i am using elimination method

to solve x and y

5x(3) -4y(3) -8×3

7x(2)+6y(2) = 9×2

15x-12y=-24 equation 3rd

14x+12y=18 equation 4th

add these two equation 15x+14x-12y+12y=-24+18

29x=-6

X=-6/29

substitute x=-6/29en equation 1st

5x-4y=-8

5(-6/29)+-4y=-8

4y=(30/29)-8

4y=(30-29-8)/29

4y=-202/29 2y=-101/29

y=-101/58

we get the value of x and y now on representing these two line on graph i put

these two lines intersect at point p point p is (-6/29,-101/58)