Math, asked by riyabiswas4777, 11 months ago

5x+5y=40,x+y=8. What is the solution?


Anonymous: ___k off

Answers

Answered by mitajoshi11051976
1
  \textbf{\underline{\underline{Answer :-}}} <br />Answer :-<br />​	<br /><br />​	<br /><br /><br />The Length of the Rectangle is 24 cm.<br /><br />\textbf{\underline{\underline{Explanation :-}}} <br />Explanation :-<br />​	<br /><br />​	<br /><br /><br />\textsf{\underline{\underline{Given :}}} <br />Given :<br />​	<br /><br />​	<br /><br /><br />The Diagonal measures = 25 cm<br /><br />The Width = 7 cm<br /><br />\textsf{\underline{\underline{To Find :}}} <br />To Find :<br />​	<br /><br />​	<br /><br /><br />The Length of the Rectangle<br /><br />\textsf{\underline{\underline{Solution :}}} <br />Solution :<br />​	<br /><br />​	<br /><br /><br />❖ \textsf{\underline{By Pythagoras theorum :}} <br />By Pythagoras theorum :<br />​	<br /><br /><br />Refer The Attachment.<br /><br />⟹ Hypotenuse : 25 cm = AD<br /><br />⟹ Base : x = CD<br /><br />⟹ Height : 7 cm = AC<br /><br />★ (Hypotenuse)² = (Base)² + (Height)²<br /><br />\sf{\implies} \: {25}^{2} = {x}^{2} + {7}^{2}⟹25 <br />2<br /> =x <br />2<br /> +7 <br />2<br /><br /><br />\sf{\implies} \: 625 = {x}^{2} + 49⟹625=x <br />2<br /> +49<br /><br />\sf{\implies} \: {x}^{2} = 625 - 49⟹x <br />2<br /> =625−49<br /><br />\sf{\implies} \: {x}^{2} = 576⟹x <br />2<br /> =576<br /><br />\sf{\implies} \: x = \sqrt{576}⟹x= <br />576<br />​	<br /><br /><br /><br /><br />⟹ 576 = 2 × 2 × 2 × 2 × 2 × 2 × 3 × 3<br /><br />⟹ 2 × 2 × 2 × 3<br /><br />⟹ 24<br /><br />\sf{\implies} \: x = 24⟹x=24<br /><br />{\boxed{\boxed{\sf{x = 24}}}} <br />x=24<br />​	<br /><br />​	<br /><br /><br />⛬ The Length of the Rectangle is 24 cm.
Answered by Gaurav19012005
0
if x and y are equal to 8 then
X may be 4 and y also 4.
now
5x+5y=40
5×4+5×4 = 40
20+20= 40
satisfied
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