Question

5x(6x^2-3x+1)+2 find its value for
I)X=3
ii)X=-1/2
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Answer 1

Answer:

Hope this may help you.

Answer 2

i) 5×3 [6×(3^2)-3×3+1]+2

=15 [6×9-9+1]+2

=15 [54-9+1]+2

=15 [54-8]+2

=15 [46]+2

=15×48

=720

ii) 5×(-1/2)[6×(-1/2)^2-3(-1/2)+1]+2

=-5/2 [6×(1/4)-3/2+1]+2

=-5/2 [3/2-3/2+1]+2

=-5/2 [1]+2

=-5/2×1+2

=-5/2+2

=-5+4/2

=-1/2

Step-by-step explanation:

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