5x-6y+30=0;5x+4y-20=0 plot graphically
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Answer:
your answer is y =5 and x= 0
Step-by-step explanation:
subtract eq ll from l
5x-6y+30-(5x+4y-20)= 0
=> 5x-6y+30-5x-4y+20=0
=> -10y = -50
=> y = 5
putting the value of y in eqn l
5x- 6×5+30=0
=> 5x= -30+30
=> 5x = 0
=> x= 0
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