Question

5x-6y=9=0
3x+4y=25
find x and y using substitution method

Answer 1

Answer:

5x-6y-9=0. (1 equation)

3x+4y-25=0. (2 equation)

Multiplying equation 2 by 5 and equation 1 by 3 we get,

15x-18y-27=0. (3 equation)

15x+20y-125=0. (4 equation)

Now, Solving equations 3 & 4 by substitution method

Substracting equation 4 from 3, we get,

15x-18y-27=0

-15x-20y+125=0

x portion will be cancelled out and remaining is

-38y+97=0

38y=97

y=2.55

Substituting the value of y in equation 1 we get,

5x-6×2.55-9=0

5x-24.3=0

5x=24.3

x=4.86