Question

(5x-7) / (2x+1 ) = (7x+1) / (7x-5)

Answer 1

Answer:

$x_{1} = \frac{ 83 }{ 42 }-\frac{\sqrt{ 4033 }}{ 42 }\\\\x_{2} = \frac{ 83 }{ 42 }+\frac{\sqrt{ 4033 }}{ 42 }$

Step-by-step explanation:

$\frac{5x-7}{2x+1}=\frac{7x+1}{7x-5}\\\\(5x-7)(7x-5)=(2x+1)(7x+1)\\\\35x^2-74x+35=14x^2+9x+1\\\\21x^2-83x+34=0\\\\WKT\\\\for\;ax^2+bx+c=0\\\\x=\frac{-b+|\sqrt{b^2-4ac}|}{2a}\\\\Therefore\;\;here\\\\\;\;x_{1} = \frac{ 83 }{ 42 }-\frac{\sqrt{ 4033 }}{ 42 }\\\\x_{2} = \frac{ 83 }{ 42 }+\frac{\sqrt{ 4033 }}{ 42 }$

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