Question

5x+7y=19 and 11x+6y=23 elimination method​

Answer 1

Answer:

Step-by-step explanation:

5x+7y=19 ----- (a)

11x+6y=23 ------(b)

(a) * 6=> 30x+42y= 114

(b) * 7=> 77x+42y= 161

(a)-(b)=> -47x= -47

=> x= 1

putting x=1 in eq---> (a)

11+7y=19

7y= 8

y=8/7

Answer 2

Answer:

Given :-

5x + 7y = 19 and 11x + 6y = 23 by elimination method

Solution:-

5x + 7y = 19 . . . . (1)

11x + 6y = 23 . . . .(2)

Multiply equation (1) by 11 and (2) by 5, we get

55x + 77y = 209 . . . . (3)

55x + 30y = 115 . . . . .(4)

Adding (3) and (4) we get,

55x + 77y = 209

55x + 30y = 115

(-) (-) (-)

____________________

47y = 94

y = 94/47

y = 2

Substituting the value of y = 2 in equation (1) we get,

5x + 7y = 19

➪ 5x + 7(2) = 19

➪ 5x + 14 = 19

➪ 5x = 19 - 14

➪ 5x = 5

➪ x = 5/5

➪ x = 1

∴ The value of x = 1, y = 2 is the solution of the system of the given equations.