Question

√5x-8x+3√5 solve the equation

Answer 1

$\textbf{Hey!!}$



Note:- There is an error in the question. It should be



$\sqrt{5} x {}^{2} - 8x + 3 \sqrt{5} = 0 \\ \\ = > \sqrt{5} x {}^{2} - 3x - 5x + 3 \sqrt{5} = 0 \\ \\ = > x( \sqrt{5} x - 3) - \sqrt{5} ( \sqrt{5} x - 3) = 0 \\ \\ = > ( \sqrt{5} x - 3)(x - \sqrt{5} ) = 0 \\ \\ = > \sqrt{5} x - 3 = 0 \: \: or \: \: x - \sqrt{5} = 0 \\ \\ = > x = \frac{3}{ \sqrt{5} } \: \: or \: \: x = \sqrt{5}$





$\textbf{Hope it helps!}$