5x-9=1/y, x+1/y=3 by simultaneous linear equation
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5x−9=y1
⇒ 5xy−9y=1 ----- ( 1 )
x+y1=3
⇒ xy+1=3y
⇒ xy−3y=−1
Multiplying both sides by 3, we get
⇒ 3xy−9y=−3 ----- ( 2 )
Subtracting eqation ( 2 ) by ( 1 ) we get,
2xy=4
∴ xy=2
Substituing xy=2 in equation ( 1 ) we get,
⇒ 5(2)−9y=1
⇒ 10−9y=1
⇒ 9y=9
∴ y=1
Now, substituting value of y in ( 1 ) we get,
⇒ 5x(1)−9(1)=1
⇒ 5x−9=1
∴ 5x=10
∴ x=2
⇒ (x,y)=(2,1)
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