Math, asked by kavitapatil185185, 7 months ago

5x-9y =-3
5x-10y=-5

solve this equation​

Answers

Answered by sankalpjha9643
5

Step-by-step explanation:

hope you got it............

Attachments:
Answered by Anonymous
4

Question:-

\sf{Find\:the\:value\:of\:x\:and\:y\:from\:the\:following\:equation:-}

\sf{5x - 9y = -3}

\sf{5x - 10y = -5}

Solution:-

\sf{5x - 9y = -3\:\: ------> (i)}

\sf{5x - 10y = -5\:\: -----> (ii)}

\sf{From\:eq.(i)}

\sf{5x - 9y = -3}

= \sf{5x = -3+9y}

=> \sf{x = \dfrac{ -3 + 9y}{5}}

Now,

\sf<u>{</u><u>Substituting</u><u>\</u><u>:</u><u> </u><u>t</u><u>he</u><u>\</u><u>:</u><u> </u><u>value</u><u>\</u><u>:</u><u> </u><u>of</u><u>\</u><u>:</u><u> </u><u>x</u><u>\</u><u>:</u><u> </u><u>in</u><u> </u><u>\</u><u>:</u><u> </u><u>eq</u><u>.</u><u>(</u><u>ii</u><u>)</u>}

= \sf{5x - 10y = -5}

= \sf{5\times\dfrac{\bigg(-3+9y}{5\bigg)} -10y = -5}

=> \sf{-3+9y -10y = -5}

=> \sf{-3 - y = -5}

=> \sf{-y = -5+3}

=> \sf{-y = -2}

=> \sf{y = 2}

\sf{Putting\:the\:value\:of\:y\:in\:eq.(i)}

= \sf{5x - 9y = -3}

= \sf{5x - 9\times2 = -3}

=> \sf{5x -18 = -3}

=> \sf{5x = -3+18}

=> \sf{5x = 15}

=> \sf{x = \dfrac{15}{5}}

=> \sf{x = 3}

\sf{\therefore\: x = 3,\: y = 2}

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