5x+d=0,3x-d=1 ,find the value of X and d
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Answered by
1
5x + d = 0 ...(1)
3x - d = 1 ...(2)
adding (1) and (2)
5x + d = 0
3x - d = 1
= 8x = 1
x = 1/8
putting value of x in eq(1)
5*1/8 + d = 0
5/8 + d = 0
d = -5/8
hence value of x = 1/8 and d = -5/8
3x - d = 1 ...(2)
adding (1) and (2)
5x + d = 0
3x - d = 1
= 8x = 1
x = 1/8
putting value of x in eq(1)
5*1/8 + d = 0
5/8 + d = 0
d = -5/8
hence value of x = 1/8 and d = -5/8
yrd:
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Answered by
0
5x+d=0...(1)
3x-d=1...(2)
Add.(1)(2).
8x=1
X=1/8.
So, 5*1/8+d=0
d= -5/8.
3x-d=1...(2)
Add.(1)(2).
8x=1
X=1/8.
So, 5*1/8+d=0
d= -5/8.
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