5x=secA. , 5/X=tanA...
3rd question...
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It is given that
5X=secA and 5/X=tanA
5(x^2-1/x^2) is the given equation
Expand it into 5x^2-5/x^2
Or,
5×(SecA/5)^2-5×(5/tanA)^2,
Which equals,
Sec^2A/5 - Tan^2A/5,
But sec^2A-Tan^2A=1,
Therefore the value of the equation is,
=1/5
5X=secA and 5/X=tanA
5(x^2-1/x^2) is the given equation
Expand it into 5x^2-5/x^2
Or,
5×(SecA/5)^2-5×(5/tanA)^2,
Which equals,
Sec^2A/5 - Tan^2A/5,
But sec^2A-Tan^2A=1,
Therefore the value of the equation is,
=1/5
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