5x sq - 8x-4 find the zeros of the polynomial and relatn blw zeroes and coefficient
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Given,
p(x) = 5x² - 8x - 4
==> p(x) = 5x² - 10x + 2x - 4
==> p(x) = 5x( x - 2) + 2(x - 2)
==> p(x) = (x - 2)(5x + 2)
∴ Zeroes are 2 , -2/5
We know,
==> Sum of zeroes = - (coefficient of x) / (coefficient of x²)
==> 2 + (-2/5) = -(-8)/5
==> (10 - 2) / 5 = 8/5
==> 8/5 = 8/5
Also,
==> Product of zeroes = (constant term) / (coefficient of x²)
==> 2 × -2/5 = -4/5
==> -4/5 = -4/5
Hence, Proved.
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