Question

5x+y=20,10x-2y=50 by substitution method​

Answer 1

Answer:

x=20-y/5

put value of x

10(20-y/5)-2y=50

40-2y-2y=50

40-4y=50

-4y=10

y= -5/2

10x-2(-5/2)=50

10x+5=50

10x=45

x=9/2

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Answer 2

Answer:

x = 9/2 and y = -5/2

Step-by-step explanation:

The given equations are :

5x + y = 20       ...(1)

10x - 2y = 50    ...(2)

From equation (1), we get;

5x + y = 20

5x = 20 -y

x = (20 - y)/5

Substituting x = (20 - y)/5 in equation (2), we get;

10 (20 - y)/5 - 2y = 50

(200 - 10y)/5 -2y = 50

(200 - 10y -10y)/5 = 50

200 - 20y = 50 x 5

200 - 20y = 250

-20y = 250 - 200

-20y = 50

y = 50/-20

y = -5/2

Substituting the value of y in equation (1), we get;

5x + y = 20

5x + (-5/2) = 20

5x - 5/2 = 20

(10x - 5)/2 = 20

10x - 5 = 20 x 2

10x - 5 = 40

10x = 40 + 5

10x = 45

x = 45/10

x = 9/2

Hope it helps u...