5x+y=26,x+5y=10 by substitution method
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◉ 5x + y = 26 .......( i)
◉ x + 5y = 10 ....... ( ii )
Now, From eq ( i ) we can write
- ↪️ 5x + y = 26
- ↪️️ 5 x = 26 - y
- ↪️ x = 26 - y / 5 ...... ( iii )
Substituting the value of " X " in eq ( ii ) , we get -
= >> x + 5y = 10
= >> ( 26 - y /5 ) + 5y = 10
= >> 26 - y + 25y /5 = 10
= >> 26 - 26y = 50
= >> -26y = 50 - 26
= >> -26 y = 24
= >> y = -12/13
. ° . 
Putting the value of y in eq ( i) , we get
☯ 5x + y = 26
- ↪️ 5x + ( -12/13) = 26
- ↪️ 5x = 26 + 12/13
- ↪️ 5x = 338 + 12 / 13
- ↪️ 5x = 350 / 13
- ↪️ x = 350/13/5
- ↪️x = 70 / 13
. °. 
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