Question

5x-y+4z=5 2x+3y+5z=2 5x-2y+6z=-1 solve by inversion method

Answer 1

Given : 5x-y+4z=5 2x+3y+5z=2 5x-2y+6z=-1

To find : Value of x , y & z

Solution:

5x-y+4z = 5       Eq1

2x+3y+5z = 2    Eq2

5x-2y+6z = -1     Eq3

2Eq1  - Eq3

=>  5x + 2z  =  11     Eq4

3Eq1 + Eq2

=> 17x  + 17z  = 17

=> x + z  = 1        Eq5

Eq4  - 2Eq5

=> 3x  = 9

=>  x  = 3

    z = - 2

5x-y+4z = 5=> 15 - y  -8 = 5  =>y  = 2

x = 3 ,  y = 2  , z = -2

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