5x + y = 6
x - 3y = 8
linear pair equation solve by substitution
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Hello user..here is your answer ❤❤
5 x + y = 6
y = 6 - 5 x......(1)
Putting value of y = 6 - 5 x in second quation given ...
x - 3 y = 8
therefore, x - 3( 6-5x) = 8
x - 18 + 15 x = 8
16 x = 26
x = 13/8
putting value of x in y = 6-5x
y = 6- 5*13/8
y = 6- 65/8
y =(48-65)/8
y = -17/8
Hope it helps..❤❤
5 x + y = 6
y = 6 - 5 x......(1)
Putting value of y = 6 - 5 x in second quation given ...
x - 3 y = 8
therefore, x - 3( 6-5x) = 8
x - 18 + 15 x = 8
16 x = 26
x = 13/8
putting value of x in y = 6-5x
y = 6- 5*13/8
y = 6- 65/8
y =(48-65)/8
y = -17/8
Hope it helps..❤❤
newpadhai:
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Answered by
1
hope it will help you ❤❤❤
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