Math, asked by saitanmayi02, 16 days ago

5x²-12x-9=0 by all methods

Answers

Answered by puspitapanda27
0

Step-by-step explanation:

Solve by factors.

\displaystyle 5x^2-12x-95x2−12x−9

(5x^2+3x)+(-15x-9)(5x2+3x)+(−15x−9)

Solve.

5x^2+3x=x(5x+3)5x2+3x=x(5x+3)

\displaystyle -3*5x-3*3−3∗5x−3∗3

Common term of 3.

\displaystyle -3(5x+3)−3(5x+3)

\displaystyle x(5x+3)-3(5x+3)x(5x+3)−3(5x+3)

Common term of 5x+3.

\displaystyle(5x+3)(x-3)(5x+3)(x−3)

\displaystyle (5x+3)(x-3)=0(5x+3)(x−3)=0

\displaystyle 5x+3=05x+3=0

Subtract by 3 from both sides.

\displaystyle 5x+3-3=0-35x+3−3=0−3

Solve.

\displaystyle 5x=-35x=−3

Divide by 5 from both sides.

\displaystyle \frac{5x}{5}=\frac{-3}{5}55x=5−3

Solve.

\Large\boxed{x=-\frac{3}{5}}x=−53

\displaystyle x-3=0x−3=0

Then, you add by 3 from both sides.

\displaystyle x-3+3=0+3x−3+3=0+3

Solve.

Add the numbers from left to right.

\displaystyle 0+3=\boxed{3}0+3=3

\Large\boxed{X=3}X=3

\Large\boxed{X=-\frac{3}{5}, \quad X=3}

x=3 or x=-3/5

Answered by bhim76
0

Step-by-step explanation:

5 {x}^{2}  - 12x - 9 = 0

By using quardratic formula,

x =  \frac{ - b\pm \sqrt{ {b}^{2}  - 4ac} }{2a}

x =  \frac{ - ( - 12)  \pm \sqrt{ {12}^{2}  - 4(5)( - 9)} }{2(5)}

=> x =  \frac{12\pm \sqrt{144  + 180} }{10}

=> x =  \frac{12\pm \sqrt{324} }{10}

=> x =  \frac{12\pm18}{10}

=> \boxed{x =  \frac{12 + 18}{10} =  \frac{30}{10}  = 3 }

=> \boxed{x =  \frac{12 - 8}{10}  =  \frac{ - 6}{10}  =  -   \frac{ 3}{5} }

By completing the square,

5 {x}^{2}    - 12x - 9 = 0

=> 5 {x}^{2}  - 12x = 9

multiplying  \frac{1}{5} to both sides

=>  \frac{1}{5}  (5 {x}^{2} - 12x ) =  \frac{1}{5} (9)

=>  {x}^{2}  -  \frac{12}{5} x =  \frac{9}{5}

adding ( \frac{12}{10} )^{2} to both sides,

=>   {x}^{2}   -  \frac{12}{5} x +  { (\frac{12}{10}) }^{2}  =  \frac{9}{5}  +  {( \frac{12}{10} )}^{2}

=>  {(x -  \frac{12}{10} )}^{2}  =  \frac{9}{5}  +  \frac{144}{100}

=>  {(x -  \frac{12}{10} )}^{2}   =  \frac{324}{100}

=> x -  \frac{12}{10}  =\pm  \sqrt{ \frac{324}{100} }

=> x = \pm \frac{18}{10}   +  \frac{12}{10}

=> \boxed{x =  \frac{18}{10}   +  \frac{12}{10}  =  \frac{30}{10}  = 3}

=> \boxed{x =   - \frac{18}{10}  +  \frac{12}{10}  =  \frac{ - 6}{10}  =  -  \frac{ 3}{5}}

By Factorization,

5 {x}^{2}   - 12x - 9 = 0

=> 5 {x}^{2}  - 15x + 3x - 9 = 0

=> 5x(x - 3) + 3(x - 3) = 0

=> (x - 3)(5x + 3) = 0

=> x - 3 = 0 =>  x = 3

=> 5x  +  3 = 0 => x = -  \frac{3}{5}

Similar questions