5x2 + 13x + k = 0 value of k?
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Answer:
k=5
Step-by-step explanation:
Let one root of the given that other zero is Reciprocal the one zero.
So,
Other zero=1/Alpha.
Given polynomial is 5x
2
+13x+k=0.
Here,
A=coefficient of x
2
B=coefficient of x
And,C=constant term.
Product of zeroes =C/A
Alpha ×1/Alpha =K/5
1=K/5
K=5
Then,
We get k=5.
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