Math, asked by vansh6314, 1 year ago

5x²-2√15x+3=0 solve by factorisation method

Answers

Answered by sonalpriya6205
7
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Answered by SteffiPaul
4

Given,

  • The quadratic equation 5x^2 -2\sqrt{15}x +3 = 0 is given.

To find,

  • We have to factorize the given quadratic equation.

Solution,

5x²-2√15x+3=0 can be factorized as (\sqrt{5}x -\sqrt{3})(\sqrt{5}x  -\sqrt{3}).

We can simply factorize the given quadratic equation 5x^2 -2\sqrt{15}x +3 = 0splitting the middle terms,

            =  5x^2 -2\sqrt{15}x +3 = 0

            = 5x^2 -\sqrt{15}x-\sqrt{15} x+ 3 = 0

Taking \sqrt{5}x common from the first two terms and \sqrt{5} common from last two terms, we get

            = \sqrt{5}x ( \sqrt{5} x-\sqrt{3})-\sqrt{3}(\sqrt{5}x-\sqrt{3})

Taking \sqrt{5} x-\sqrt{3} common, we get

            =(\sqrt{5}x -\sqrt{3})(\sqrt{5}x  -\sqrt{3})

Hence, 5x²-2√15x+3=0 can be factorized as (\sqrt{5}x -\sqrt{3})(\sqrt{5}x  -\sqrt{3}).

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