Question

5x²+26x+5=0 by completing square method

Answer 1

HLO FRIEND....^_^



5x²+26x+5=0

= 5x^2 + 26x + 5 = 0

= 5x^2 + 25x + x + 5 = 0

= 5x( x + 5 ) +1 ( x + 5 ) = 0

= (x+5) (5x+1) Ans....



Hope its help u my friend^_^....

be brainly..

Answer 2

Answer:

Values of x is (-5) or $( - \frac{1}{5} )$

Step-by-step explanation:

Given,$5 {x}^{2} + 26x + 5 = 0$

By Square method,

$5 {x}^{2} + (25 + 1)x + 5 = 0 \\ 5 {x}^{2} + 25x + x + 5 = 0 \\5x(x + 5) + (x + 5) = 0 \\ (x + 5)(5x + 1) = 0$

We know product of two term is zero then they are separately zero.

$x + 5 = 0$and $5x + 1 = 0$

So,

$x + 5 = 0 \\ x = - 5$

and

$5x + 1 = 0 \\ 5x = - 1 \\ x = - \frac{1}{5}$

Here values of x is $( - 5)$or$( - \frac{1}{5} )$

This is a problem of Algebra

Some important formulas of Algebra,

(a + b)² = a² + 2ab + b²

(a − b)² = a² − 2ab − b²

(a + b)³ = a³ + 3a²b + 3ab² + b³

(a - b)³ = a³ - 3a²b + 3ab² - b³

a³ + b³ = (a + b)³ − 3ab(a + b)

a³ - b³ = (a -b)³ + 3ab(a - b)