Math, asked by konarverma, 11 months ago

5x² - 29x + 20 find the zeroes and verify relationship



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Answers

Answered by gourirupa
2

Answer: (5x - 4) , (x - 5)

Step-by-step explanation:

5x^2 - 29x + 20

In the middle coefficient we have -29 , and in the other 2 coefficients we have 5 and 20 , 5 x 20 = 100

So we wish to find some x,y such that x + y = -29 , as well as x * y = 100

Clearly such two x and y are -25,-4 . So :-

5x^2 - 25x - 4x + 20

5x(x - 5) - 4(x - 5)

(5x - 4)(x - 5)

Verification: (5x - 4)(x - 5)

5x^2 - 25x - 4x + 20 (After multiplying each term)

5x^2 - 29x + 20 which was needed to be shown

I hope this is helpful to you .

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