5x²-2x-3=0 by formula method
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We usually discuss the nature of the roots of the quadratic equation. However, the nature of the equation is that it is factorizable, with real roots such that
(5x+3)(x−1)=0(5x+3)(x−1)=0
The graph crosses the x-axis twice at x=1x=1and x=−35x=−35, which are its roots.
For this equation,
dydx=10x−2dydx=10x−2
So the equation has an extreme value at;
10x−2=010x−2=0
So x=0.2x=0.2
Small excursions around this value such as x=0.19x=0.19 and x=0.21x=0.21 show that the x=0.2x=0.2is a resting point (point of inflection) as the curve continues evolving.
d2ydx2=10d2ydx2=10 shows that the curve gets steeper at an increasing rate as x increases.
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Hey mate
Step-by-step explanation:
Ur answer is above given by Tanya sis
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