5x²-2y+9 ; 3x²+5y-7 Subtract the second polynomial from the first.
Answers
Answered by
80
Hey Friend___
Here ia ur answer...
(5x²–2y+9) – (3x²+5y–7)
= 5x²–2y+9–3x²–5y–7
= 2x²–7y+2
Hope it helps u...☺☺☺☺
Here ia ur answer...
(5x²–2y+9) – (3x²+5y–7)
= 5x²–2y+9–3x²–5y–7
= 2x²–7y+2
Hope it helps u...☺☺☺☺
Answered by
30
Answer:
2x² - 7y + 16
Step-by-step explanation:
As per the question,
We have been provided the two polynomials, which are :
P₁ = 5x²-2y+9
P₂ = 3x²+5y-7
Now on subtracting the second equation that is P₂ from the first polynomial P₁
We get,
P₁ - P₂ = (5x²-2y+9) - (3x²+5y-7)
= (5x² - 3x²) -(2y + 5y) + (9 + 7)
= 2x² - 7y + 16
Hence, the required answer is = 2x² - 7y + 16
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