Question

√5x² – 3/6x - √20 = 0
solve by quadratic formula

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Answer 1

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since,

$d = {b}^{2} - 4ac$

$d = ( { \frac{ - 3}{6} })^{2} - 4( \sqrt{5})( - \sqrt{20} )$

$d = \frac{9}{36} + 40$

$d = \frac{1}{4} + 40$

$d = 40.25$

$x = \frac{ - b \frac{ + }{ - } \sqrt{d} }{2a}$

$x = \frac{ - ( - \frac{3}{6}) \frac{ + }{ - } \sqrt{40.25} }{2( \sqrt{5}) }$

$x = \frac{ \frac{3}{6} \frac{ + }{ - } \sqrt{40.25} }{2 \sqrt{5} }$

Answer 2

Answer:

6√5x² - 3x - 6√20 / 6 = 0

3 ( 2√5x² - x - 2√20 ) /6 = 0

2√5x² - x - 2√20 / 2 = 0

2√5x² - x - 2√20 = 0x2

2√5x² - x - 2√20 = 0

a = 2√5

b = -1

c = -2√ 20

D = b² - 4ac

D = (-1)²- 4(2√5)(-2√20)

D = 1 - 4(2√5)(-2x2√5)

D = 1 - 4(2√5)(-4√5)

D = 1 + 4(40)

D = 1 + 160

D = 161

x = -b ± √D / 2a

x = -(-1) ± √161 /2(2√5)

x = 1 + √161 /4√5

x = 1 +√161 /4√5

and

x = 1 - √161 /4√5

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