Question

5x²-7x+1 find zeros of quadratic polynomial ​

Answer 1

5x²-7x+1=0

by quadratic equation

comparing this eq with standard form ax²+bx+c=0

a= 5, b= -7 and c= 1

D= b²-4ac = 49 -4×5×1 = 49-20 = 29

x= -b+- √D/2a = 7 +- √29/ 10 = 0.7+- √29/10