5x²-7x+1 find zeros of quadratic polynomial
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5x²-7x+1=0
by quadratic equation
comparing this eq with standard form ax²+bx+c=0
a= 5, b= -7 and c= 1
D= b²-4ac = 49 -4×5×1 = 49-20 = 29
x= -b+- √D/2a = 7 +- √29/ 10 = 0.7+- √29/10
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